This requires:

(1) Find the integral

(2) Substitute 9 into the integral

(3) Substitute 4 into the integral

(4) Subtract the result of Step (3) from the result of Step (2).

`int_4^9(2x+3sqrtx)dx=[x^2+2x^(3//2)]_4^9`

`=[9^2+2(9)^(3//2)]-[4^2+2(4)^(3//2)]`

`=135-32`

`=103`

Explanation: The integral of `sqrt(x)` is as follows (I have not included the constant):

`intsqrtx dx=intx^(1//2)dx`

`=(x^(3//2))/(3//2)`

`=(2x^(3//2))/3`

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