Using grouping method, we have:

- Product of the outer 2 terms is (3
*x*^{2})(−14*y*^{2}) = −42*x*^{2}*y*^{2} - Inner term:
*xy*

So we are looking for 2 terms whose **product** is −42*x*^{2}*y*^{2} and whose **sum** is *xy*.

A little bit of thinking gives us: 7*xy* and −6*xy.*

So we can factor our trinomial as follows:

3*x*^{2} + *xy *− 14*y*^{2}

= 3

x^{2}+ 7xy− 6xy− 14y^{2}= (3

x^{2}+ 7xy) − (6xy+ 14y^{2})=

x(3x+ 7y) − 2y(3x+ 7y)= (

x −2)(3yx+ 7y)

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