This time, the **product of the outer terms** is 2*n*^{2} × −7 = −14*n*^{2}.

The **inner term ** is −13*n*.

So we are looking for 2 terms whose product is −14*n*^{2} and whose sum is −13*n*.

Those 2 terms are −14*n* and *n*.

(This step is nearly always easier to do with grouping method, compared to what we were doing at the top of the page.)

So we write:

2*n*^{2} − 13*n* − 7

= 2

n^{2}− 14n+n− 7= (2

n^{2}− 14n) + (n− 7)= 2

n(n− 7) + (1)(n− 7)= (2

n+ 1)(n− 7)