This time, the product of the outer terms is 2n2 × −7 = −14n2.

The inner term is −13n.

So we are looking for 2 terms whose product is −14n2 and whose sum is −13n.

Those 2 terms are −14n and n.

(This step is nearly always easier to do with grouping method, compared to what we were doing at the top of the page.)

So we write:

2n2 − 13n − 7

= 2n2 − 14n + n − 7

= (2n2 − 14n) + (n − 7)

= 2n(n − 7) + (1)(n − 7)

= (2n + 1)(n − 7)