We recognise that it is in the form: `y=u/v`.

We can use the substitutions:

`u = 2x^3` and `v = 4 − x`

Using the quotient rule, we first need to find:

`(du)/(dx)=6x^2`

and

`(dv)/(dx)=-1`

Then

`(d(u/v))/(dx)=(v(du)/(dx)-u(dv)/(dx))/v^2`

`=((4-x)(6x^2)-(2x^3)(-1))/((4-x)^2)`

`=(24x^2-6x^3+2x^3)/((4-x)^2)`

`=(24x^2-4x^3)/((4-x)^2)`