First, we simplify our log expression using the log law:

log an = n log a

We can write

y = ln(1 2x)3 = 3 ln(1 2x)

Then we put

u = 1 − 2x

So

`u’ = (du)/dx=-2`

So our answer is:

`(dy)/(dx)=3 (u’)/u`

`=3xx(-2)/(1-2x)`

`=(-6)/(1-2x)`