` x=theta^3csc 2 theta `

If we let `u=theta^3` and `v=csc 2 theta`, then

`(dx)/(d theta) =u(dv)/(d theta)+v (du)/(d theta)`

`=theta^3(-csc 2 theta cot 2 theta)(2)+` `csc 2 theta(3 theta^2)`

`=theta^2(csc 2 theta)(-2 theta cot 2 theta+3)`

Get the Daily Math Tweet!
IntMath on Twitter