"Obtaining not more than one" means we choose either `0` or `1` defective.

Let event E1 be "obtaining zero defectives" and E2 be "obtaining `1` defective item".

(a) Events E1 and E2 are mutually exclusive, so

P(E1 or E2) = P(E1) + P(E2) = 0.34 + 0.46 = 0.8

(b) `P("more than 1") = 1 − 0.8 = 0.2`

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