Since `10` out of `100` students are both French and female, then

`P(A\ "and"\ B) = 10/100`

Also, `60` out of the `100` students are French, so

`P(B) = 60/100`

So the required probability is:

`P(A|B)=frac{P(A\ "and"\ B)}{P(B)}=frac{10/100}{60/100}=1/6`

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