123-1-2-35101520xy(x)Open image in a new page

The curve y = x2 + 2, showing the portion under the curve from x = 1 to x = 2.

`text[Area] = int_a^b f(x) dx`

`=int_1^2(x^2+2)dx`

`=[(x^3)/(3)+2x]_1^2`

`=[(8/3 + 4 )-(1/3 + 2)]`

`=13/3\ text[units]^2`