Before we can proceed, we need to find x in terms of y.

Now when `x = 0`, `y = 3` and when `x = 2`, `y = 4`.

So we have:

`y=mx+c`

`=1/2x+3`

This gives us `x = 2y − 6`.

To apply the formula, we have:

`x = 2y − 6 = 2(y − 3) `

`y` is the variable of integration

`w = 9800\ "N m"^-3`

`a = 3`

`b = 4`

So we have:

`"Force"=wint_a^bxy\ dy`

`=9800 int_3^4 2y(y-3)\ dy`

`=19600 int_3^4 (y^2-3y) text[d]y`

`=19600 [(y^3)/(3)-(3)/(2)y^2]_3^4`

`=19600[((4^3)/(3)-3/2(4)^2)` `{:-((3^3)/(3)-3/2(3)^2)]`

`=19600[-2.667 - (-4.5)]`

`=35900\ text[N]`