`V_C=1/C inti\ dt `

Note: `1\ "nF" = 10^-9"F"`; and `1\ μ"s" = 10^-6"s"`;

Also, `0.042t\ "mA" = 0.042 × 10^-3t\ "A"`

`V_C = (0.042 times 10^-3)/(8.5 times 10^-9)int t\ dt`

`=4.94 times 10^3 (t^2)/(2)+K`

`=2.47 times 10^3t^2 + K`

Now, we are told that when `t = 0`, `V_C= 0`.

So `K= 0`.

Thus

`V_C=2.47 times 10^3 t^2`

So when `t = 2.00\ μ"s"`, we have:

`V_C = 2.47 times 10^3(2 times 10^-6)^2`

`=9.882 times 10^-9`

`=9.88\ text[nV]`