Using the Square of a Difference formula
(x − y)2 = x2 − 2xy + y2,
we have:
(3p − 4q)2
= (3p)2 − (2)(3p)(4q) + (4q)2 = 9p2 − 24pq + 16q2
= (3p)2 − (2)(3p)(4q) + (4q)2
= 9p2 − 24pq + 16q2