The question requires us to divide 1 by (√3 − √2).

We need to multiply top and bottom of the fraction by the conjugate of (√3 − √2).

The conjugate is easily found by reversing the sign in the middle of the radical expression. In this case, our minus becomes plus. So the conjugate of (√3 − √2) is (√3 + √2).

`frac{1}{sqrt3 - sqrt2}`

` = frac{1}{sqrt3 - sqrt2} times frac{sqrt3 + sqrt 2}{sqrt3 + sqrt2}`

`= frac{sqrt3 + sqrt2}{(sqrt3)^2 - (sqrt(2))^2}`

`=frac{sqrt3 + sqrt2}{3-2}`

`=sqrt3 + sqrt2`

After we multiply top and bottom by the conjugate, we see that the denominator becomes free of radicals (in this case, the denominator has value 1).