Using the Log Law `log\ a^n= n\ log\ a`, we can write:

y = ln(2x³ − x)² = 2 ln(2x³ − x)

Put

`u = 2x^3 − x`

so

`u^' = 6x − 1`

This gives us:

`(dy)/(dx)=2(6x^2-1)/(2x^3-x`

`x ≠ ±sqrt(0.5)`,

`x ≠ 0`

NOTE: We need to be careful with the domain of this solution, as it is only correct for certain values of x.

The graph of y = ln(2x³ - x)² is defined for all x except

` ±sqrt(0.5), 0`

Its graph is as follows:

The graph of y = 2 ln(2x³ - x), however, is only defined for a more limited domain (since we cannot have the logarithm of a negative number.)

So we can only have x in the range -√0.5 < x < 0 and x > √0.5.

So when we find the differentiation of a logarithm using the shortcut given above, we need to be careful that the domain of the function and the domain of the derivative are stated.