First, we write the right hand side as:

`y = 2x\ sin\ x + (2 − x^2) cos\ x`.

We have 2 products. The first term is the product of `(2x)` and `(sin\ x)`. The second term is the product of `(2-x^2)` and `(cos\ x)`.

So, using the Product Rule on both terms gives us:

`= (2x) (cos\ x) + (sin\ x)(2) + [(2 − x^2) (−sin x) + (cos\ x)(−2x)]`

`= cos\ x (2x − 2x) + (sin\ x)(2 − 2 + x^2)`

`= x^2sin\ x`