First we must separate the variables:

`(2\ dy)/y=((x+1)dx)/x`

This gives us: `(2\ dy)/y=(1+1/x)dx`

We now integrate:

`{: (int(2\ dy)/y=int(1+1/x)dx),(2\ ln\ y=x+ln\ x+K):}`

Go back to Integration: Basic Logarithm Form if you are rusty on this integration.