The graph connecting the generic data points `(1, 1)`, `(2, 3)` and `(3, 8)` is as follows.

One way of finding the radius of curvature is to find the (unique) parabola passing through these 3 points. Parabolas are excellent for approximating curves in a local region. (See more on Parabolas.)

We proceed as follows. In general, a parabola has the form:

y=ax^{2}+bx+c

Substituting our given points (1, 1), (2, 3) and (3, 8) into the general form of the parabola gives us 3 equations in 3 unknowns:

1 =

a+b+c3 = 4

a+ 2b+c8 = 9

a+ 3b+ c

Solving this set of 3 simultaneous equations gives us:

a= 1.5

b= −2.5

c= 2

So the parabola passing through the points `(1, 1), (2, 3)` and `(3, 8)` is

y= 1.5x^{2}− 2.5x+ 2

We see this parabola passes through each of the 3 points:

Using this as our function (which we can only do in this local region for the original data points), we apply the formula for the radius of curvature:

`text(Radius of curvature)=([1+((dy)/(dx))^2]^(3//2))/|(d^2y)/(dx^2)|`

We need to find the first and second derivatives and evaluate them at the center point `(2, 3)`.

`(dy)/(dx)=3x-2.5`

At `x = 2` (the middle of our 3 points), `dy/dx = 3.5`

Now for the second derivative:

`(d^2y)/(dx^2)=3`

So the radius of curvature at the middle point (2, 3) is:

` [1+(dy/dx)^2]^(3text(/)2)/(|(d^2y)/(dx^2)|)=[1+(3.5)^2]^(3//2)/3`

`=16.08`

So we've found a parabola that approximates our function for the local area near our data points. Then we found the radius of curvature - that is, the radius of a circle that "fits" our curve near our data points.

Here are the 3 data points, the parabola we found, and the circle indicating the curvature for the given 3 points. It has radius `16.08`.

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