The velocities they reach are 13.5 ms^-1 and 17 ms^-1 respectively.

Similar to the problem above, we have:

First car (red) distance at time t = 1/2 × 13.5 (t + t - 15)

Second car (blue) distance at time t = 1/2 × 17 (t + t - 20)

The distance when they meet is the same, so:

1/2 × 13.5 ×(2t - 15) = t = 1/2 × 17 × (2t - 20)

Solving gives:

Time = 19.625 s

Distance = 163.68