a. Velocity = 55 × 3 = 165 ms-1

b. The acceleration is a constant 55 ms-2, so at t = 3 s, the acceleration will be 55 ms-2.

c. The distance travelled in 3 seconds is 165 × 1.5 = 247.5 m. We obtain this from the area under the line between 0 and 3 (i.e. the area of the triangle).

d. The graph:

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