x3 - 2x2 + x ≥ 0 x(x2 - 2x + 1) ≥ 0 x(x - 1)2 ≥ 0
x3 - 2x2 + x ≥ 0
x(x2 - 2x + 1) ≥ 0
x(x - 1)2 ≥ 0
Our critical values are: x = 0 or 1.
Testing as above, we find our solution set is: x ≥ 0.