The first step with this example is to factor out x2 from each term:
6x4 − 13x3 + 5x2 = x2(6x2 − 13x+ 5)
Using grouping method on the (6x2 − 13x + 5) part, we have:
So we are looking for 2 terms whose product is 30x2 and whose sum is -13x.
Those 2 terms are -10x and -3x.
So we can factor our trinomial as follows:
6x4 − 13x3 + 5x2 |
= x2(6x2 − 13x+ 5) = x2[6x2 − 10x − 3x + 5] = x2[(6x2 − 10x) − (3x − 5)] = x2[2x(3x − 5) − (1)(3x − 5)] = x2[(2x − 1)(3x − 5)] = x2(2x − 1)(3x − 5) |