This problem requires us to solve the equation:
5t+2 = e2t
We need to use loge because of the base e on the right hand side.
ln (5t+2) = ln (e2t)
(t + 2) ln 5 = 2t ln e
Now, ln e = 1, and we need to collect t terms together:
t ln 5 + 2 ln 5 = 2t
t (ln 5 - 2) = - 2 ln 5
So
is the required time.
Graph
We can see on the graph that the 2 curves intersect at t = 8.2, as we found above.