We have an implicit function:

sin-1(x + y) + y = x2.

Taking the first term, sin-1(x + y), and letting

u = x + y,

we differentiate the inverse sine using:

implicit

Now du/dx = 1 + dy/dx.

Using the above, and differentiating implicitly term-by-term gives:

implicit

Multiplying throughout by:

implicit

we have:

implicit

Subtracting 1 from both sides:

implicit

Grouping the dy/dx terms:

implicit

Dividing both sides by:

1 + implicit

We obtain the required solution:

implicit