We have an implicit function:
sin-1(x + y) + y = x2.
Taking the first term, sin-1(x + y), and letting
u = x + y,
we differentiate the inverse sine using:
Now du/dx = 1 + dy/dx.
Using the above, and differentiating implicitly term-by-term gives:
Multiplying throughout by:
we have:
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Subtracting 1 from both sides:
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Grouping the dy/dx terms:
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Dividing both sides by:
1 +
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We obtain the required solution: