We can write the DE in i and q as follows (call it Equation (1)):
Differentiating gives a 2nd order DE in i:
Auxiliary equation:
,
Solution is: ![]()
So
![]()
(This means at t = 0, i = A = 0 in this case.)
So
We need to find the value of B.
Differentiating gives:

At t = 0, ![]()
Returning to equation (1): ![]()
Now, at time t = 0, ![]()
So ![]()
So B = 19.
Therefore,
![]()
We need to set it up in terms of q only, to give us a DE which SNB can solve:

To get i, we simply differentiate:

