We can write the DE in i and q as follows (call it Equation (1)):

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Differentiating gives a 2nd order DE in i:

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Auxiliary equation:

$m^{2}+10m+50=0$,

Solution is: MATH

So

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(This means at t = 0, i = A = 0 in this case.)

So

$i=e^{-5t}B\sin 5t$

We need to find the value of B.

Differentiating gives:

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At t = 0, $\dfrac{di}{dt}=5B$

Returning to equation (1): MATH

Now, at time t = 0, MATH

So MATH


So B = 19.


Therefore,

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SNB Solution:

We need to set it up in terms of q only, to give us a DE which SNB can solve:

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To get i, we simply differentiate:

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7_2ndODE_force__35.png