We have not seen how to solve "2 mesh" networks before. We consider the total voltage of the inner loop and the total voltage of the outer loop. We then solve the resulting two equations simultaneously.

We use the basic formula:

Considering the inner loop:

Now, considering the outer loop:

We now solve (1) and (2) simultaneously:

(1) × 3 − (2) × 2 gives:

Solving using SNB with the boundary condition i₁(0) = 0 gives:

The graph of our answer is:

Now, from equation (1), we have:

The graph of i₂ is: