(a) We solve it using the formula:
We have:
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(b) At
A
(c) ![]()
![]()
(d)

V
The graph of
and
:

TC for this example is: ![]()
NOTE (just for interest): If we could not use the formula in (a), and we did not use separation of variables, we could recognise that the DE is 1st order linear and so we could solve it using an integrating factor.
We use the formula: ![]()
The required DE is: ![]()
![]()
I.F. = ![]()
![]()
Since
, we have
.
So ![]()
It works :-)