For Z1 (the upper part of the circuit), we have:
XL = 2π fL = 2π (60)(0.0200) = 7.540 Ω

Z1 = R1 + j(XL − XC)
= 100 + j(7.540 - 2210.485)
= 100 - 2202.9j
= 2205.21 ∠ − 87.40° Ω
For Z2 (the lower part of the circuit), we have:

Z2 = R2 + j(XL - XC)
= 110 + j(- 1105.243)
= 1110.7 ∠ − 84.32° Ω
So the total impedance, ZT, is given by:
This last line gives us ZT = 59.9 - 736.5j Ω
Now:
So the total current taken from the supply is 203 mA and the phase angle is 85°.