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For Z1 (the upper part of the circuit), we have:

XL = 2π fL = 2π (60)(0.0200) = 7.540 Ω

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Z1 = R1 + j(XLXC)

= 100 + j(7.540 - 2210.485)

= 100 - 2202.9j

= 2205.21 ∠ − 87.40° Ω

For Z2 (the lower part of the circuit), we have:

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Z2 = R2 + j(XL - XC)

= 110 + j(- 1105.243)

= 1110.7 ∠ − 84.32° Ω

So the total impedance, ZT, is given by:

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This last line gives us ZT = 59.9 - 736.5j Ω

Now:

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So the total current taken from the supply is 203 mA and the phase angle is 85°.