Firstly, express the LHS in the form R sin(θ − α) (Note the negative sign!):

So

Now, solving the original equation gives:

Sine is positive in Quadrants I and II.

So, from calculator, we get

OR

And this gives us:

OR

Are these answers correct?

We can see from the graph that in the domain 0° ≤ θ < 360°, the only two angles which give a value of 0.8 are 82.3° and 207.2°. So our answer is correct.