4. Half-Angle Formulas

by M. Bourne

 

We will develop formulas for the sine and cosine of a half angle.

We start with the formula for the cosine of a double angle that we met in the last section.

cos 2θ = 1− 2sin2 θ

Half Angle Formula - Sine

Now, if we let

mathImage

then 2θ = α and our formula becomes:

cos α = 1 − 2sin2 (α/2)

We now solve for

mathImage

(that is, we get sin(α/2) on the left of the equation and everything else on the right):

2sin2 (α/2) = 1 − cos α

sin2 (α/2) = (1 − cos α)/2

Solving gives us the following sine of a half-angle identity:

sin alpha/2

The sign of mathImagedepends on the quadrant in which α/2 lies.

If α/2 is in the first or second quadrants, the formula uses the positive case:

sin alpha/2

If α/2 is in the third or fourth quadrants, the formula uses the negative case:

sin alpha/2 - negative case

Half Angle Formula - Cosine

Using a similar process, with the same substitution of mathImage(so 2θ = α) we subsitute into the identity

cos 2θ = 2cos2 θ − 1 (see cosine of a double angle)

We obtain

cos alpha/2

Reverse the equation:

cos alpha/2

Add 1 to both sides:

cos alpha/2

Divide both sides by 2

cos alpha/2

Solving for cos(α/2), we obtain:

cos alpha/2

As before, the sign we need depends on the quadrant.

If α/2 is in the first or fourth quadrants, the formula uses the positive case:

cos alpha/2

If α/2 is in the second or third quadrants, the formula uses the negative case:

cos alpha/2

Example 1

Find the value of sin 15° using the sine half-angle relationship given above.

Answer


Example 2

Find the value of cos 165° using the cosine half-angle relationship given above.

Answer


Example 3:

Show that mathImage

Answer


Exercises: Evaluating and Proving Half-Angle Identities

1. Use the half angle formula to evaluate sin 75°.

Answer


2. Find the value of mathImage if mathImage where 0° < α < 90°.

Answer


3. Prove the identity: mathImage


Answer


4. Prove the identity: mathImage

Answer





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